Electrophilic and Nucleophilic Aromatic Substitution
The electrophilic and
nucleophilic aromatic substitution reactions are the elemental reactions in
organic and inorganic chemistry.
Electrophilic Aromatic
Substitution is the reaction in which an electrophile substitutes hydrogen in
the aromatic ring. In contrast, Nucleophilic Aromatic Substitution is the
reaction in which a nucleophile substitutes a leaving group in the aromatic ring.
Electrophiles are
electron-deficient species in a chemical reaction that readily accept electrons
from electron-rich species to form a bonding. These can be Lewis Acid and
Bronsted Acid.
For example, halogen
molecules like Fluorine (F₂) and Chlorine (Cl₂), acids like hydronium ion (H₃O+), etc.
Nucleophiles are
electron-rich species searching for a positive centre, the nucleus of an atom,
to form bonding in a chemical reaction. Examples of nucleophiles are halogen
anions (–, Cl–), etc., cyanide ion (CN–), ammonia(NH3)
Differentiation between Electrophilic and Nucleophilic
Aromatic Substitution Reaction
Substitutes
·
Electrophilic
Aromatic Substitution – Here, an electrophile attacks the aromatic ring.
The electrophile being electron deficit seeks for the electron cloud
in aromatic compounds, which forms an electron pool with C-C pi– electrons.
·
Nucleophilic Aromatic
Substitution: Here, a nucleophile attacks the aromatic ring. The
nucleophile has a positive centre and hence gets bonded with C. In this atom,
there is a leaving group as the C–atom has a relative negative charge due
to the delocalisation of electrons because of the
electron-withdrawing groups present in the ring.
Aromatic Compound
Electrophilic Aromatic
Substitution- The aromatic compound is nucleophilic, as it is
electron-rich.
C6H6, a stable benzene ring
with a C–C pi(Ï€) electron cloud, acts as a nucleophilic, tending to attract the
positive centre of the electrophile, which has fewer electrons.
Nucleophilic Aromatic
Substitution- The aromatic compound is electron-deficient, hence
electrophilic.
C6H2(NO2)3 is
the aromatic compound with three electron-withdrawing groups and
hence is an electron-deficient compound that tends to attract electron-rich
nucleophiles.
Leaving Group
·
Electrophilic
Aromatic Substitution: The leaving group is H+. The electrophilic aromatic
substitution reaction mechanism includes the deprotonation of the tetrahedral
carbon. Hence H+ is the leaving group that leaves the ring.
·
Nucleophilic Aromatic
Substitution: The leaving group is not H+. It can be anything like
Chlorine. Here, the leaving group is halides, mostly Fluorine, Chlorine,
Bromine, etc. The C–X bond breaks and X (halide) leaves the ring.
Place of Attack
·
Electrophilic
Aromatic Substitution– The place of binding of electrophile depends on the
ortho-, meta- or para- positions that constitute the steric and electronic
factors. The steric hindrance plays a role in the stability and arrangement of
the atoms and molecules of the compound.
·
Nucleophilic Aromatic
Substitution: The place of substitution depends on the position of the
leaving group. The ortho-, meta- or para- position though not directly govern
the place of attack, but the rate of Reaction is greatly affected by the
position of the leaving and electron-withdrawing groups. For example, the
nucleophilic aromatic Substitution reaction form-nitrophenyl fluoride is slower
than p-nitrophenyl fluoride.
Mechanism
Electrophilic Aromatic Substitution
Step 1: Bonding of electrophile by the pi(Ï€)
electrons.
Here, the electrophile, an
electron-rich species, attacks the pi(Ï€) bond aromatic ring (benzene ring, C6H6 ).
The pi (Ï€) bond acts as a nucleophile here for the electrophile and attracts
it. The delocalisation of the electron due to the attachment of the electrophile
induces a positive charge to the attached carbon atom.
The electron from the pi(Ï€)
bond forms a bond with the electrophile, while the aromaticity of the compound
is lost, forming a positively charged intermediate with a carbocation.
The electron-rich
electrophilic substituents stabilise the electron-poor intermediate formed.
Step 2: The tetrahedral carbon deprotonates
From the intermediate formed
in the first step, the C–H bond breaks, and thus the H+ goes off from the
ring, and the aromaticity of the ring is restored, forming the C–C pi(Ï€) bond.
Hence the electrophilic
aromatic substitution product C6H5E is formed.
Nucleophilic Aromatic Substitution
Step 1: Attack the nucleophile on the
electron-deficient aromatic compound.
The attachment of the
nucleophile compound to the aromatic compound breaks the ring’s
aromaticity. The delocalisation of the electron due to the attachment of the
nucleophile induces a negative charge to the attached carbon atom. Hence, it
forms a negatively charged intermediate. This is a rate-limiting phase.
The electron-withdrawing
group (NO2) stabilises the electron-rich intermediate.
Step 2: The leaving group is expelled from the ring.
The negatively charged
intermediate now expels the leaving group (for example, F2) from the ring.
Hence the aromaticity of the ring is regained, and a nucleophilic aromatic
substitution product is formed.
Hence, the reagent is an
electrophile for electrophilic aromatic substitution reaction, whereas it uses
a nucleophilic reagent for nucleophilic aromatic substitution reaction.
The intermediate form is
positively charged in the electrophilic aromatic substitution reaction, whereas
the intermediate is negatively charged for the nucleophilic aromatic
substitution reaction.
Deprotonation occurs in the
electrophilic aromatic substitution reaction, whereas the case is not the same
for the nucleophilic aromatic substitution reaction.
The Rate of Reaction is Increased by
For electrophilic aromatic
substitution reaction, a catalyst is mostly a Lewis acid, such as AlCl3 or
FeCl3.
For nucleophilic aromatic
substitution reaction, the reaction rate increases with the number of
electron-withdrawing groups (NO2) present in the aromatic compound.
Conclusion
The electrophilic aromatic
substitution and the nucleophilic aromatic substitution reactions exhibit a
similar substitution, except that these reactions go in reverse polarity. Apart
from the important differences, these share some common aspects, such as in
both the reactions, electron sharing is observed.
To add to that, covalent
bonds are formed for both of these reactions and along with the production of
leaving groups (H+, F–), there is also the displacement of different groups in
the substrate compound.
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