Preparation of 0.1 Molar and 1 Molar Hydrochloric Acid
solution
Preparation of 0.1 Molar Hydrochloric Acid
solution
¨ For
the preparation of 0.1 M Hydrochloric Acid (HCl), take 8.3ml of HCl and dilute
it with carbon-dioxide free water up to 1000 ml.
¨ Molecular
Weight of HCl = 1+35.5= 36.5
¨ Mass
in gram= Molarity x molecular weight x required volume
1000
¨ Mass
in gram= 0.1 x 36.5x 1000 = 3.65
gram
1000
¨ Now
convert mass into volume by using following formula
¨ Density
= Mass
Volume
Re
arrange the formula, Volume = Mass
density
Density
of HCl = 1.19
Volume
= 3.65/ 1.19 = 3.06 ml
¨ The
above said volume is for 100% pure HCl, however the available HCl is 37% pure,
hence the volume required will become
¨ 3.06 x 100 = 8.3 ml
37
¨ Hence
to prepare 1 liter, 0.1 molar solution of HCl we will take 8.3 ml of HCl in
carbon-dioxide free 1 liter water.
Preparation of 1M Hydrochloric Acid Solution
¨ For
the preparation of 1 M Hydrochloric Acid (HCl), take 83ml of HCl and dilute it
with carbon-dioxide free water up to 1000 ml.
¨ Molecular
Weight of HCl = 1+35.5= 36.5
¨ Mass
in gram= Molarity x molecular weight x required volume
1000
¨ Mass
in gram= 1 x 36.5x 1000 = 36.5
gram
1000
¨ Now
convert mass into volume by using following formula
¨ Density
= Mass
Volume
Re
arrange the formula, Volume = Mass
density
Density
of HCl = 1.19
Volume =
36.5/ 1.19 = 30.67 ml
¨ The
above said volume is for 100% pure HCl, however the available HCl is 37% pure,
hence the volume required will become
¨ 30.67 x 100 = 82.89 (83) ml
37
¨ Hence
to prepare 1 liter, 1 molar solution of HCl we will take 83 ml of HCl in
carbon-dioxide free 1 liter water.
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